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JEE Main 202330 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
30 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2023 · 30 January · Morning Shift · Chemistry · Solutions

A solution containing 2g of a non-volatile solute in 20g of water...

A solution containing 2g2g of a non-volatile solute in 20g20g of water boils at 373.52K373 . 52K. The molecular mass of the solute is _____ gmol−1{gmol}^{- 1}. (Nearest integer)

Given, water boils at 373K,Kb373K, {K}_{b} for water =0.52Kkgmol−1= 0 . 52Kkg{mol}^{- 1}

Correct answer

0

Step-by-step solution

Elevation in boiling point:
⇒ΔTb=373.52−373=0.52⇒ {\Delta T}_{b} = 373 . 52 - 373 = 0 . 52

ΔTb=Kb⋅m{\Delta T}_{b} = {K}_{b} \cdot m

⇒0.52=0.52×2Molar Mass of Solute×120×10−3⇒ 0 . 52 = 0 . 52 \times \dfrac{2}{\text{Molar Mass of Solute}} \times \dfrac{1}{20 \times {10}^{- 3}}

Molar Mass of solute=100g/mol= 100g / mol

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