When Fe _ 0 . 93 O is heated in presence of oxygen, it converts to...

$A: {Fe}_{0 . 93}O \to {Fe}_{2}{O}_{3}$

The valence factor of ${Fe}_{0 . 93}O$, $nf = \left(3 - \dfrac{200}{93}\right) \times 0 . 93$

$nf = 0 . 79$

Hence, the equivalent weight $= \dfrac{Molecularweight}{0 . 79}$

$B: 2x + \left(0 . 93 - x\right) \times 3 = 2$

$x = 0 . 79$

${Fe}^{2 +} = 0 . 79, {Fe}^{3 +} = 0 . 14$

$C:$ In ${Fe}_{0 . 93}O$, ${O}^{2 -}$ ions forms the lattice and iron ions occupies the voids in the lattice. As sufficient number of irons are not available, this metal oxide is said to be metal difficient.

$D:$