5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0 . 1 M solution ? Given : Molar Mass of Na , O and H is 23 , 16 and 1 g mol &#8211

Question

5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0 . 1 M solution ? Given : Molar Mass of Na , O and H is 23 , 16 and 1 g mol &#8211; 1 respectively

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Molarity od stock solution = moles &#160; of &#160; solute Volume &#160; of &#160; solution &#160; in &#160; L = 5 / 40 0 . 45 M 1 V 1 = M 2 V 2 5 / 40 0 . 45 &#215; V 1 = 0 . 1 &#215; 500 1000 V 1 = 180 1000 = 0 . 18 &#160; L

5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0 . 1 M solution ? Given : Molar Mass of Na , O and H is 23 , 16 and 1 g mol – 1 respectively

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5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0 . 1 M solution ? Given : Molar Mass of Na , O and H is 23 , 16 and 1 g mol &#8211; 1 respectively

Correct answer

Step-by-step solution

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5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0 . 1 M solution ? Given : Molar Mass of Na , O and H is 23 , 16 and 1 g mol – 1 respectively