If O 2 gas is bubbled through water at 303 K , the number of millimoles of O 2 gas that dissolve in 1 litre of water is____(Nearest integer) (Given : Henry's Law constant for O 2 at 303 K is 46 . 82 k bar and partial pressure of O 2 = 0 . 920 bar) (Assume solubility of O 2 in water is too small, nearly negligible)

Step-by-step solution

p = K H × x 0 . 920 = 46 . 82 × 10 3 bar × mol   of   O 2 mol   of   H 2 O 0 . 920 = 46 . 82 × 10 3 × mol   of   O 2 1000 18 0 . 920 = 46 . 82 × 18 × n O 2 0 . 920 46 . 82 × 18 = n O 2 ⇒ 1 . 09 × 10 - 3 = n 0 2 ⇒ m   mol   of   O 2 = 1   millimole