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JEE Main 202228 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
28 July
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2022 · 28 July · Evening Shift · Chemistry · Solutions

A gaseous mixture of two substances A and B , under a total...

A gaseous mixture of two substances AA and BB, under a total pressure of 0.8atm0 . 8atm is in equilibrium with an ideal liquid solution. The mole fraction of substance AA is 0.50 . 5 in the vapour phase and 0.20 . 2 in the liquid phase. The vapour pressure of pure liquid AA is____atm.(Nearest integer)

Correct answer

0

Step-by-step solution

Raoult’s law states that a solvent’s partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.

Raoult’s law is valid only in the case of ideal solutions

PA=PoAχA(AccordingtoRaoult′slaw){P}_{A} = {P}^{o}A{χ}_{A}\left(AccordingtoRaoult ' slaw\right)

PA=PTYA(AccordingtoDalton′slaw)PT=TotalpressurePA=vapourpressureofAinsolution{P}_{A} = {P}_{T}{Y}_{A}\left(AccordingtoDalton ' slaw\right){P}_{T} = Totalpressure{P}_{A} = vapourpressureofAinsolution

PoA=VapourpressureofpureliquidA{P}^{o}A = VapourpressureofpureliquidA

χA=MolefractionofcomponentAinliquidphase{χ}_{A} = MolefractionofcomponentAinliquidphase

YA=MolefractionofcomponentAingaseousphase{Y}_{A} = MolefractionofcomponentAingaseousphase

So, PA=PoAχA=YAPT{P}_{A} = {P}^{o}A{χ}_{A} = {Y}_{A}{P}_{T}

PAo(0.2)=0.5×0.8{P}_{A}^{o}\left(0 . 2\right) = 0 . 5 \times 0 . 8

PAo=2atm{P}_{A}^{o} = 2atm

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