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JEE Main 202225 JulyEvening Shift

Exam: JEE Main
Year: 2022
Date: 25 July
Shift: Evening Shift
Subject: Chemistry
Chapter: Solutions

JEE Main 2022 · 25 July · Evening Shift · Chemistry · Solutions

Two solutions A and B are prepared by dissolving 1g of non-volatile...

Two solutions

A

and

B

are prepared by dissolving

1g

of non-volatile solutes

X

and

Y

. respectively in

1kg

of water. The ratio of depression in freezing points for

A

and

B

is found to be

1: 4

. The ratio of molar masses of

X

and

Y

is

Options

A $1: 4$
B $1: 0 . 25$
C $1: 0 . 20$
D $1: 5$

Correct answer

B. $1: 0 . 25$

Step-by-step solution

We know that for an non-electrolyte
$∆ {T}_{f} = {K}_{f}mwherem = molality$
$\dfrac{{\Delta T}_{fx}}{{\Delta T}_{fy}} = \dfrac{{k}_{f} \cdot {m}_{x}}{{k}_{f} \cdot {m}_{y}} = \dfrac{\dfrac{1}{{M}_{x}}}{\dfrac{1}{{M}_{y}}}$
$⇒ \dfrac{1}{4} = \dfrac{{M}_{y}}{{M}_{x}}$
$⇒ {M}_{x}: {M}_{y} = 1: 0 . 25$

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