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JEE Main 202226 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
26 July
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2022 · 26 July · Evening Shift · Chemistry · Solutions

The elevation in boiling point for 1 molal solution of non-volatile...

The elevation in boiling point for 11 molal solution of non-volatile solute AA is 3K3K. The depression in freezing point for 22 molal solution of AA in the same solvent is 6K6K. The ratio of Kb{K}_{b} and Kf{K}_{f} i.e., Kb/Kf{K}_{b} / {K}_{f} is 1:X1: X. The value of XX is

Correct answer

0

Step-by-step solution

We know that

ΔTb=iKbm1ΔTf=iKfm2{\Delta T}_{b} = {iK}_{b}{m}_{1}{\Delta T}_{f} = {iK}_{f}{m}_{2}

And for non-volatile solute i=1i = 1.

ΔTbΔTf=Kb×1Kf×2⇒36=12=KbKf×12\dfrac{{\Delta T}_{b}}{{\Delta T}_{f}} = \dfrac{{K}_{b} \times 1}{{K}_{f} \times 2} ⇒ \dfrac{3}{6} = \dfrac{1}{2} = \dfrac{{K}_{b}}{{K}_{f}} \times \dfrac{1}{2}

KbKf=11⇒X=1\dfrac{{K}_{b}}{{K}_{f}} = \dfrac{1}{1} ⇒ X = 1

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