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The vapour pressures of two volatile liquids A and B at 25 ° C are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0 . 3 mole fraction of A , then the mole fraction of liquid B in the vapour phase is x 17 . The value of x is

Correct answer

0

Step-by-step solution

Since, y A = p ° A × x A p ° A × x A + p ° B × x B and x A = 0 . 3 and x B = 0 . 7 y A = 50 × 0 . 3 50 × 0 . 3 + 100 × 0 . 7 y A = 15 85 . Y B 1 - y B = P B 0 P A 0 X B 1 - X B ⇒ y B 1 - y B = 100 50 0 . 7 0 . 3 = 14 3 ⇒ y B = 14 17

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