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JEE Main 202227 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
27 June
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2022 · 27 June · Morning Shift · Chemistry · Solutions

2g of a non-volatile non-electrolyte solute is disolved in 200g of...

2g2g of a non-volatile non-electrolyte solute is disolved in 200g200g of two different solvents AA and BB whose ebullioscopic constants are in the ratio of 1:81: 8. The elevation in boiling points of AA and BB are in the ratio xy(x:y)\dfrac{x}{y}\left(x: y\right). The value of yy is____(Nearest Integer)

Correct answer

0

Step-by-step solution

Given : (Kb)A(Kb)B=18\dfrac{{\left({K}_{b}\right)}_{A}}{{\left({K}_{b}\right)}_{B}} = \dfrac{1}{8}

∴(ΔTB)A(ΔTB)B=(Kb)A⋅m(Kb)B⋅m=18=xy∴ \dfrac{{\left({\Delta T}_{B}\right)}_{A}}{{\left({\Delta T}_{B}\right)}_{B}} = \dfrac{{\left({K}_{b}\right)}_{A} \cdot m}{{\left({K}_{b}\right)}_{B} \cdot m} = \dfrac{1}{8} = \dfrac{x}{y}

∵xy=18∵ \dfrac{x}{y} = \dfrac{1}{8}

∴y=8∴ y = 8 (nearest integer)

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