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JEE Main 202226 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
26 June
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2022 · 26 June · Evening Shift · Chemistry · Solutions

The osmotic pressure exerted by a solution prepared by dissolving 2...

The osmotic pressure exerted by a solution prepared by dissolving 2.0g2 . 0g of protein of molar mass 60kgmol−160kg{mol}^{- 1} in 200mL200mL of water at 27°C27 ° C is____PaPa. [integer value] (use R=0.083LR = 0 . 083L bar mol−1K−1{mol}^{- 1}{K}^{- 1})

Correct answer

0

Step-by-step solution

Osmotic pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane.It is a colligative property.

π=CRTWhere,π=OsmoticpressureC=MolarityT=Temperature.\pi = CRTWhere, \pi = OsmoticpressureC = MolarityT = Temperature .

π=CRT=[2×10360×103×200]×8.31×300×1000=415Pa\pi = CRT = \left[\dfrac{2 \times {10}^{3}}{60 \times {10}^{3} \times 200}\right] \times 8 . 31 \times 300 \times 1000 = 415{P}_{a}

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