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JEE Main 202224 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
24 June
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2022 · 24 June · Evening Shift · Chemistry · Solutions

A company dissolves ' x ' amount of CO _ 2 at 298K in 1 litre of...

A company dissolves 'xx' amount of CO2{CO}_{2} at 298K298K in 11 litre of water to prepare soda water. X=×10−3gX = \times {10}^{- 3}g. (nearest integer)

(Given: partial pressure of CO2{CO}_{2} at 298K=0.835298K = 0 . 835 bar. Henry's law constant for CO2{CO}_{2} at 298K=1.67kbar298K = 1 . 67kbar. Atomic mass of H,CH, C and OO is 1,121, 12, and 6gmol−16g{mol}^{- 1}, respectively)

Correct answer

0

Step-by-step solution

Using Henry’s law
Pgas = KH .Xgas

10−3X0.835=1.67[nCO2nCO2+55.5]10−3X0.5=[nCO2nCO2+55.5]nCO255.5=0.5X10−3nCO2=27.75X10−3WCO2=27.75X10−3X44=1221X10−3g{10}^{- 3}X0 . 835 = 1 . 67\left[\dfrac{{n}_{{CO}_{2}}}{{n}_{{CO}_{2}} + 55 . 5}\right]{10}^{- 3}X0 . 5 = \left[\dfrac{{n}_{{CO}_{2}}}{{n}_{{CO}_{2}} + 55 . 5}\right]\dfrac{{n}_{{CO}_{2}}}{55 . 5} = 0 . 5X{10}^{- 3}{n}_{{CO}_{2}} = 27 . 75X{10}^{- 3}{W}_{{CO}_{2}} = 27 . 75X{10}^{- 3}X44 = 1221X{10}^{- 3}g

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