JEE Main202224 Jun 2022Evening ShiftChemistrySolutionsActual
A company dissolves ' x ' amount of CO 2 at 298 K in 1 litre of water to prepare soda water. X = × 10 - 3 g . (nearest integer) (Given: partial pressure of CO 2 at 298 K = 0 . 835 bar. Henry's law constant for CO 2 at 298 K = 1 . 67 kbar . Atomic mass of H , C and O is 1 , 12 , and 6 g mol - 1 , respectively)
Correct answer
0
Step-by-step solution
Using Henry’s law P gas = K H .X gas 10 - 3 X 0 . 835 = 1 . 67 n CO 2 n CO 2 + 55 . 5 10 - 3 X 0 . 5 = n CO 2 n CO 2 + 55 . 5 n CO 2 55 . 5 = 0 . 5   X 10 - 3 n CO 2 = 27 . 75 X 10 - 3 W CO 2 = 27 . 75 X 10 - 3 X 44 = 1221 X 10 - 3 g