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The osmotic pressure of blood is 7 . 47 bar at 300 K . To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL - 1 is (Molar mass of glucose = 180 g mol - 1 , R = 0 . 083 Lbar - 1 mol - 1 ) (Nearest integer)

Correct answer

0

Step-by-step solution

Osmotic pressure, π = iCRT i = van't hoff factor C = concentration in molarity R = universal gas constant T = temperature C = Molarity = moles Litre = ω GMω / Litre π = iCRT i = 1   for   glucose as it neither associates nor dissociates in solution. 7 . 47 = 1 × C × 0 . 083 × 300 7 . 47 = 1 × ω 180 × 0 . 083 × 300 ω = 7 . 47 × 180 0 . 083 × 300 = 54   g / Lit

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