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JEE Main 202224 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
24 June
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2022 · 24 June · Morning Shift · Chemistry · Solutions

The osmotic pressure of blood is 7 . 47 bar at 300K . To inject...

The osmotic pressure of blood is 7.477 . 47 bar at 300K300K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL−1{gL}^{- 1} is (Molar mass of glucose =180gmol−1= 180g{mol}^{- 1}, R=0.083Lbar−1mol−1R = 0 . 083{Lbar}^{- 1}{mol}^{- 1}) (Nearest integer)

Correct answer

0

Step-by-step solution

Osmotic pressure, π=iCRT\pi = iCRT

i=i = van't hoff factor

C=C = concentration in molarity

R=R = universal gas constant

T=T = temperature

C=C = Molarity

=molesLitre= \dfrac{moles}{Litre}

=ωGMω/Litre= \dfrac{\omega}{GM \omega} / Litre

π=iCRT\pi = iCRT

i=1forglucosei = 1forglucose as it neither associates nor dissociates in solution.

7.47=1×C×0.083×3007 . 47 = 1 \times C \times 0 . 083 \times 300

7.47=1×ω180×0.083×3007 . 47 = 1 \times \dfrac{\omega}{180} \times 0 . 083 \times 300

ω=7.47×1800.083×300=54g/Lit\omega = \dfrac{7 . 47 \times 180}{0 . 083 \times 300} = 54g / Lit

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