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JEE Main 202131 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
31 August
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2021 · 31 August · Evening Shift · Chemistry · Solutions

Sodium oxide reacts with water to produce sodium hydroxide. 20 . 0g...

Sodium oxide reacts with water to produce sodium hydroxide. 20.0g20 . 0g of sodium oxide is dissolved in 500mL500mL of water. Neglecting the change in volume, the concentration of the resulting NaOHNaOH solution is _________ ×10−1M.\times {10}^{- 1}M . (Nearest integer)
[Atomic mass : Na=23.0,O=16.0,H=1.0Na = 23 . 0, O = 16 . 0, H = 1 . 0]

Correct answer

0

Step-by-step solution

Na2O+H2O→2NaOH{Na}_{2}O + {H}_{2}O \to 2NaOH
According to reaction 2062\dfrac{20}{62} mole of Na2O{Na}_{2}O gives 4062\dfrac{40}{62} mole of NaOHNaOH
so molarity of NaOHNaOH solution is =nNaOHVml×1000=4062×1000500=8062=1.29M≈1.3M= \dfrac{{n}_{NaOH}}{{V}_{ml}} \times 1000 = \dfrac{40}{62} \times \dfrac{1000}{500} = \dfrac{80}{62} = 1 . 29M \approx 1 . 3M
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