JEE Main202131 Aug 2021Evening ShiftChemistrySolutionsActual
1 . 22 g of an organic acid is separately dissolved in 100 g of benzene K b = 2 . 6 K kg mol - 1 and 100 g of acetone K b = 1 . 7 K kg mol - 1 . The acid is known to dimerize in benzene but remain as a monomer in acetone. The boiling point of the solution in acetone increases by 0 . 17 ° C . The increase in boiling point of solution in benzene in C ∘ is x × 10 - 2 . The value of x is (Nearest integer)
Correct answer
0
Step-by-step solution
ΔT b = i × k b × molality ; m = w 1 GMM 1 × 1000 w 2 For Acetone solution 0 . 17 = 1 × 1 . 7 × 1 . 22 GMM × 1000 100 GMM of substance = 122   gm / mol For Benzene solution ΔT b = i × k b × m = 1 2 × 2 . 6 × 1 . 22 122 × 1000 100 = 0 . 13 = 13 × 10 - 2 = 13