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83 g of ethylene glycol dissolved in 625 g of water. The freezing point of the solution is ..... K. (Nearest integer) [Use : Molal Freezing point depression constant of water = 1 . 86 K kg mol - 1 Freezing point of water = 273 K Atomic masses : C : 12 . 0 u , O : 16 . 0 u , H : 1 . 0 u ]

Correct answer

0

Step-by-step solution

Δ T f = iK f × m = 1 × 1 . 86 × 83 × 1000 62 × 625 ΔT f = 3 . 984   K So, freezing point of solution = 273 - 3 . 984 = 269 . 016 ≃ 269   K

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