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JEE Main 202126 AugustEvening Shift

Exam: JEE Main
Year: 2021
Date: 26 August
Shift: Evening Shift
Subject: Chemistry
Chapter: Solutions

JEE Main 2021 · 26 August · Evening Shift · Chemistry · Solutions

83g of ethylene glycol dissolved in 625g of water. The freezing...

83g

of ethylene glycol dissolved in

625g

of water. The freezing point of the solution is ..... K. (Nearest integer)
[Use : Molal Freezing point depression constant of water

= 1 . 86Kkg{mol}^{- 1}

Freezing point of water

= 273K

Atomic masses :

C: 12 . 0u, O: 16 . 0u, H: 1 . 0u ]

Correct answer

0

Step-by-step solution

$\Delta{T}_{f} = {iK}_{f} \times m$

$= 1 \times 1 . 86 \times \dfrac{83 \times 1000}{62 \times 625}$

${\Delta T}_{f} = 3 . 984K$

So, freezing point of solution $= 273 - 3 . 984 = 269 . 016 ≃ 269K$

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