C _ 6 H _ 6 freezes at 5 . 5 ° C . The temperature at which a...

Pure Solvent: ${C}_{6}{H}_{6}\left(ℓ\right)$

Given: ${T}_{f} ° = 5 . 5 ° C$

${K}_{f} = 5 . 12 ° C / m$

:Solute is non dissociative

$∵ \Delta{T}_{f} = {k}_{f} \times m$

$⇒ \left({T}_{f}^{0} - {T}_{f}^{'}\right) = 5 . 12 \times \dfrac{\left(\dfrac{10}{58}\right)}{\left(\dfrac{200}{1000}\right)kg}mol$

$⇒ 5 . 5 - {T}_{f}^{'} = \dfrac{5 . 12 \times 5 \times 10}{58}$

$⇒ {T}_{f}^{'} = 1 . 086 ° C ≃ 1 C ∘$