The elevation of boiling point of 0 . 10m aqueous CrCl _ 3 . xNH _...

$0 . 05m$ aqueous ${CaCl}_{2}$ $= 0 . 15$molal solution of non electrolyte

Since the elevation in boiling point is double so the molality of given solution of complex $= 0 . 3m$

Hence the complex must be producing three ions in the solution, so its formula $= \left[Cr{\left({NH}_{3}\right)}_{5}Cl\right]{Cl}_{2}$

SO $X = 5$