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JEE Main 20204 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
4 September
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2020 · 4 September · Evening Shift · Chemistry · Solutions

The osmotic pressure of a solution of NaCl is 0 . 10 atm and that...

The osmotic pressure of a solution of NaClNaCl is 0.100 . 10 atm and that of a glucose solution is 0.200 . 20 atm. The osmotic pressure of a solution formed by mixing 1L1L of the sodium chloride solution with 2L2L of the glucose solution is x×10−3x \times {10}^{- 3} atm. xx is ________ (nearest integer)

Correct answer

0

Step-by-step solution

π=iCRT\pi = iCRT

On mixing two solution πfinal=π1V1+π2V2V1+V2{\pi}_{final} = \dfrac{{\pi}_{1}{V}_{1} + {\pi}_{2}{V}_{2}}{{V}_{1} + {V}_{2}}

πfinal=(0.1×1+0.2×2)3{\pi}_{final} = \dfrac{\left(0 . 1 \times 1 + 0 . 2 \times 2\right)}{3}

=0.1+0.43=0.53=5003×100−3atm= \dfrac{0 . 1 + 0 . 4}{3} = \dfrac{0 . 5}{3} = \dfrac{500}{3} \times {100}^{- 3}atm

So, X=167X = 167

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