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If 250 cm 3 of an aqueous solution containing 0 . 73 g of a protein A is isotonic with one litre of another aqueous solution containing 1 . 65 g of a protein B , at 298 K , the ratio of the molecular masses of A and B is _ _ _ _ _ _ _ _ _ _ _ × 10 − 2 (to the nearest integer).

Correct answer

0

Step-by-step solution

For isotonic solution i 1 C 1 = i 2 C 2 For protein i = 1 C 1 = C 2 ⇒     0 . 73 × 1000 M A × 250 = 1 . 65 M B × 1 M A M B = 0 . 73 × 4 1 . 65 = 1 . 77 = 177 × 10 - 2

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