Henry's constant (in kbar) for four gases α , β , γ and δ in water at 298 K is given below : α β γ δ K H 50 2 2 × 10 - 5 0 . 5 (density of water = 10 3 k gm - 3 at 298 K ) This table implies that :

Step-by-step solution

(1) From Henery's law P = k H X Higher the value of k H smaller will be solubility so γ is more soluble. (2) Though solubility of gas will decrease with increase in temperature but this conclusion can not be drawn from the given table. (3)For δ ⇒ P δ = K Hδ . X δ = 0 . 5 × 10 3 × 55 . 55 55 . 55 + 1000 18 = 250 bar . (4)For γ p γ = K H γ   × x γ = 2 × 10 - 2 55 . 5 55 . 5 + 1000 18 = 10 - 2 bar