1g of a non-volatile non-electrolyte solute is dissolved in 100g of...

Elevation in Boiling point $∆ {T}_{b} = i \times {k}_{b} \times m$

For non-electrolyte, $i = 1$

m= Molar mass of solute

${m}_{1} = molalityofsolution1{m}_{2} = molalityofsolution2$

$∆ {T}_{{b}_{1}} = {k}_{1} \times 1 \times {m}_{1}, {m}_{1} = \dfrac{1}{100 \times m} \times 1000 = \dfrac{10}{m}$

$∆ {T}_{{b}_{2}} = {k}_{2} \times 1 \times {m}_{2}, {m}_{2} = \dfrac{1}{100 \times m} \times 1000 = \dfrac{10}{m}$

${m}_{1} = {m}_{2}$

$\dfrac{∆ {T}_{{b}_{1}}}{∆ {T}_{{b}_{2}}} = \dfrac{{k}_{1}}{{k}_{2}} = 1: 5$