JEE Main20199 Apr 2019Evening ShiftChemistrySolutionsActual
Molal depression constant for a solvent is 4.0 K k g m o l - 1 . The depression in the freezing point of the solvent for 0.03   m o l   k g - 1 solution of K 2 S O 4 is: (Assume complete dissociation of the electrolyte)
Options
- A0.36 K
- B0.24 K
- C0.18 K
- D0.12 K
Correct answer
A. 0.36 K
Step-by-step solution
Depression in Freezing Point = Δ T f Δ T f = i × k f × m Molality = 0.03   m o l / k g i = 3 ;    k f = 4   K   k g / m o l Δ T f = 3 × 4 × 0.03 = 0.36   K