JEE Main20199 Apr 2019Morning ShiftChemistrySolutionsActual
The osmotic pressure of a dilute solution of an ionic compound X Y in water is four times that of a solution 0.01 M B a C l 2 in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of X Y ( i n m o l L - 1 ) in solution is
Options
- A4 × 10 - 2
- B16 × 10 - 4
- C4 × 10 - 4
- D6 × 10 - 2
Correct answer
D. 6 × 10 - 2
Step-by-step solution
Osmotic pressure π = i × C R T i = Van't hoff factor According to question, for XY i = 2 ,   B a C l 2 i = 3 π XY = 4 × π BaCl 2 2 × C × R T = 4 × 3 × 0.01 × R T C = 6 × 0.01 = 0.06   M