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JEE Main 20198 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
8 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2019 · 8 April · Evening Shift · Chemistry · Solutions

For the solution of the gases w, x, y and z in water at 298K, the...

For the solution of the gases w,x,yw, x, y and zz in water at 298K,298K, the Henry's law constants (KH)( {K}_{H} ) are 0.5,2,350.5,2, 35 and 40kbar,40kbar, respectively. The correct plot for the given data is:For the solution of the gases w, x, y and z in water at 298K, the Henry's law constants ( K _ H ) are 0.5,2, 35 andFor the solution of the gases w, x, y and z in water at 298K, the Henry's law constants ( K _ H ) are 0.5,2, 35 andFor the solution of the gases w, x, y and z in water at 298K, the Henry's law constants ( K _ H ) are 0.5,2, 35 andFor the solution of the gases w, x, y and z in water at 298K, the Henry's law constants ( K _ H ) are 0.5,2, 35 and

Options

  1. AIn the reaction of alkenes with water in the presence of an acid catalyst, what is the catalyst's role?
  2. BIn the reaction of alkenes with water in the presence of an acid catalyst, what is the catalyst's role?
  3. CIn the reaction of alkenes with water in the presence of an acid catalyst, what is the catalyst's role?
  4. DIn the reaction of alkenes with water in the presence of an acid catalyst, what is the catalyst's role?

Correct answer

A. In the reaction of alkenes with water in the presence of an acid catalyst, what is the catalyst's role?

Step-by-step solution

Pgas=KH.Xgas{P}_{gas} = {K}_{H} . {X}_{gas}

Where, Pgas{P}_{gas} is the partial pressure of gas.

KH{K}_{H} is the Henry’s constant

Xgas{X}_{gas} is the mole fraction of gas

Pgas=KH(1−XH2O){P}_{gas} = {K}_{H}\left(1 - {X}_{{H}_{2}O}\right)

Pgas=KH−KHXH2O{P}_{gas} = {K}_{H} - {K}_{H}{X}_{{H}_{2}O}

On comparing this with the equation of straight line, y=mx+cy = mx + c, the intercept, c=KHc = {K}_{H}. Thus, the gas having more value of Henry's law constant will have more value of intercept on the y-axis.

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