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JEE Main20199 Apr 2019Morning ShiftChemistrySolutionsActual

Liquid M and liquid N form an ideal solution. The vapour pressures of pure liquids M and N are 450 and 700 m m H g , respectively, at the same temperature. Then correct statements is: ( x M = M o l e f r a c t i o n o f ' M ' i n s o l u t i o n ; x N = M o l e f r a c t i o n o f ' N ' i n s o l u t i o n ; y M = M o l e f r a c t i o n o f ' M ' i n v a p o u r p h a s e ; y N = M o l e f r

Options

  1. Ax M x N > y M y N
  2. Bx M x N = y M y N
  3. Cx M x N < y M y N
  4. Dx M - y M < x N - y N

Correct answer

A. x M x N > y M y N

Step-by-step solution

P M o is given as = 450 &#160; m m &#160; o f &#160; H g . P N o is given as = 700 &#160; m m &#160; o f &#160; H g . We know that P M = x M &#215; P &#160; M O &#8594; Raoult&rsquo;s law. P N = x N &#215; P &#160; N O &#8594; Raoult&rsquo;s law. From Dalton&rsquo;s law P M = y M &#215; P T P N = y M &#215; P T So, x M &#215; P &#160; M o = y M &#215; P T &#160; &#160; &#8230; ( i ) x M &#215; P N o = y N &#215; P T &#160; &#160; &#160; &#160; &#8230; ( i i ) ( i ) &#160; ( ii ) &#160; x M x N &#215; P &#160; &#160

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