JEE Main20199 Apr 2019Morning ShiftChemistrySolutionsActual
Liquid M and liquid N form an ideal solution. The vapour pressures of pure liquids M and N are 450 and 700 m m H g , respectively, at the same temperature. Then correct statements is: ( x M = M o l e f r a c t i o n o f ' M ' i n s o l u t i o n ; x N = M o l e f r a c t i o n o f ' N ' i n s o l u t i o n ; y M = M o l e f r a c t i o n o f ' M ' i n v a p o u r p h a s e ; y N = M o l e f r
Options
- Ax M x N > y M y N
- Bx M x N = y M y N
- Cx M x N < y M y N
- Dx M - y M < x N - y N
Correct answer
A. x M x N > y M y N
Step-by-step solution
P M o is given as = 450   m m   o f   H g . P N o is given as = 700   m m   o f   H g . We know that P M = x M × P   M O → Raoult’s law. P N = x N × P   N O → Raoult’s law. From Dalton’s law P M = y M × P T P N = y M × P T So, x M × P   M o = y M × P T     … ( i ) x M × P N o = y N × P T         … ( i i ) ( i )   ( ii )   x M x N × P