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The amount of sugar C 12 H 22 O 11 required to prepare 2 L of its 0 .1 M aqueous solution is:

Options

  1. A17 .1   g
  2. B136 .8   g
  3. C68 .4   g
  4. D34 .2   g

Correct answer

C. 68 .4   g

Step-by-step solution

Molarity = Moles Volume   in   L ⇒ 0.1 = m o l e s 2 Moles of sucrose required = 2 × 0.1 = 0.2 moles Weight of sucrose = 0 .2 × 342   g = 68 .4   g

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