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JEE Main 202628 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2026 · 28 January · Evening Shift · Chemistry · Structure of Atom

The wavelength of photon ' A ' is 400 nm. The frequency of photon '...

The wavelength of photon ' A ' is 400 nm. The frequency of photon ' B ' is 1016 s−110^{16} \mathrm{~s}^{-1}. The wave number of photon ' C′C^{\prime} is 104 cm−110^{4} \mathrm{~cm}^{-1}. The correct order of energy of these photons is :

Options

  1. AC>B>A\mathrm{C}>\mathrm{B}>\mathrm{A}
  2. B B>A>C\mathrm{~B}>\mathrm{A}>\mathrm{C}
  3. C A>B>C\mathrm{~A}>\mathrm{B}>\mathrm{C}
  4. D A>C>B\mathrm{~A}>\mathrm{C}>\mathrm{B}

Correct answer

B.  B>A>C\mathrm{~B}>\mathrm{A}>\mathrm{C}

Step-by-step solution

Photon A: λA=400\lambda_A = 400 nm
EA=hcλA=6.626×10−34×3×108400×10−9=4.97×10−19E_A = \frac{hc}{\lambda_A} = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{400 \times 10^{-9}} = 4.97 \times 10^{-19} J
Photon B: νB=1016\nu_B = 10^{16} s⁻¹
EB=hνB=6.626×10−34×1016=6.626×10−18E_B = h\nu_B = 6.626 \times 10^{-34} \times 10^{16} = 6.626 \times 10^{-18} J
Photon C: νˉC=104\bar{\nu}_C = 10^4 cm⁻¹ = 10610^6 m⁻¹
λC=10−6\lambda_C = 10^{-6} m
EC=hcλC=6.626×10−34×3×10810−6=1.988×10−19E_C = \frac{hc}{\lambda_C} = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{10^{-6}} = 1.988 \times 10^{-19} J
Order: EB>EA>ECE_B > E_A > E_C
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