Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202623 January 2026Evening ShiftChemistryStructure of AtomActual

The work functions of two metals (M_ A . and .M_ B ) are in the 1: 2 ratio. When these metals are exposed to photons of energy 6 eV, the kinetic energy of liberated electrons of M_ A : M_ B is in the ratio of 2.642: 1 . The work functions (in eV) of M_ A and M_ B are respectively.

Options

  1. A1.4,2.8
  2. B2.3,4.6
  3. C1.5,3.0
  4. D3.1,6.2

Correct answer

B. 2.3,4.6

Step-by-step solution

The work functions satisfy W_A : W_B = 1:2 . Let W_A = W and W_B = 2W . Using the photoelectric equation KE = h - W , we have KE_A = 6 - W and KE_B = 6 - 2W . Given the kinetic energy ratio KE_A KE_B = 2.642 , we get 6-W 6-2W = 2.642 . Solving: 6 - W = 2.642(6 - 2W) gives 6 - W = 15.852 - 5.284W So 4.284W = 9.852 and W = 2.3 eV. Thus W_A = 2.3 eV and W_B = 4.6 eV.

Practice Structure of Atom on Quantrex Academy →

More from Structure of Atom

The 2s and the 2p orbital energies of hydrogen atom are E_ 2s ( H ) and E_ 2p ( H ) , respectively. The 2s and the 2p orbital energies of lithium atom are E_ 2s ( Li ) and E_ 2p ( 2026X ^ a+ and Y ^ b+ are hydrogen-like species. The wavelength of light absorbed during the transition between the states with principal quantum numbers n = 1 and n = 2 of X ^ a+ is . 2026Consider two radiations of wavelengths 1. ₁ = 2000 Å 2. ₂ = 6000 Å The ratio of the energies of these two radiations ( E₁ E₂ ) is ________ (Nearest integer). 2026The Bohr radius of a hydrogen like species is 70.53 pm. The species and the stationary state (n) are respectively (Given : Hydrogen atom Bohr radius is 52.9 pm) 2026If shortest wavelength of hydrogen atom in Lyman series is x , then longest wavelength in Balmer series of He ^+ is: 2026Match the List-I with List-II List-I Orbital List-II Radial nodes and nodal plane A. 2s I. 1 Radial node + two nodal planes B. 3s II. 1 Radial node + one nodal plane C. 3p III. 2 R 2026Which of the following statement(s) is/are true ? A. If two orbitals have the same value of (n + l) , the orbital with lower value of n will have lower energy. B. Energies of the o 2026Arrange the following atomic orbitals of multi electron atoms in order of increasing energy. A. n = 3, l = 2, m = +1 B. n = 4, l = 0, m = 0 C. n = 6, l = 1, m = 0 D. n = 5, l = 1, 2026 Full Structure of Atom list All JEE Main PYQs