Given below are two statements : Statement I : When an electric discharge is passed through gaseous hydrogen, the hydrogen molecules dissociate and the energetically excited hydrogen atoms produce electromagnetic radiation of discrete frequencies. Statement II : The frequency of second line of Balmer series obtained from He ⁺ is equal to that of first line of Lyman series obtained from hydrogen atom. In the light of

Step-by-step solution

Statement I: Electric discharge through H₂ causes dissociation into excited H atoms which emit discrete frequencies (line spectrum). This is true. Statement II: Using = RcZ^2 ( 1 n₁^2 - 1 n₂^2 ) For He^+ (Z=2), second Balmer line ( n₁=2, n₂=4 ): = 4Rc ( 1 4 - 1 16 ) = 3Rc 4 For H (Z=1), first Lyman line ( n₁=1, n₂=2 ): = Rc (1 - 1 4 ) = 3Rc 4 Both frequencies are equal. Statement II is true. Both statements are true.