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JEE Main 20253 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
3 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2025 · 3 April · Evening Shift · Chemistry · Structure of Atom

For electron in ' 2 s ' and ' 2 p ' orbitals, the orbital angular...

For electron in ' 2 s ' and ' 2 p ' orbitals, the orbital angular momentum values, respectively are :

Options

  1. A2 h2π\sqrt{2} \frac{\mathrm{~h}}{2 \pi} and 0
  2. Bh2π\frac{\mathrm{h}}{2 \pi} and 2 h2π\sqrt{2} \frac{\mathrm{~h}}{2 \pi}
  3. C0 and 6 h2π\sqrt{6} \frac{\mathrm{~h}}{2 \pi}
  4. D0 and 2 h2π\sqrt{2} \frac{\mathrm{~h}}{2 \pi}

Correct answer

D. 0 and 2 h2π\sqrt{2} \frac{\mathrm{~h}}{2 \pi}

Step-by-step solution

\begin{aligned} & \text{ Orbital angular momentum }=\sqrt{\ell(\ell+1)} \frac{\mathrm{h}}{2 \pi} \\ & \therefore \quad \text{ For } 2 \mathrm{ s} \text{ orbital }: \ell=0 \\ & \text{ Orbital angular momentum }=0 \\ & \therefore \quad \text{ For } 2 \mathrm{p} \text{ orbital }: \ell=1 \\ & \quad \begin{aligned} \text{ Orbital angular momentum } & =\sqrt{1(1+2)} \frac{\mathrm{h}}{2 \pi} \\ & =\sqrt{2} \frac{\mathrm{ h}}{2 \pi}\end{aligned}\end{aligned}$
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