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The calculated spin-only magnetic moments of K ₃ [ Fe ( OH )₆ ] and K ₄ [ Fe ( OH )₆ ] respectively are :

Options

  1. A3.87 and 4.90 B.M.
  2. B4.90 and 5.92 B.M.
  3. C4.90 and 4.90 B.M.
  4. D5.92 and 4.90 B.M.

Correct answer

D. 5.92 and 4.90 B.M.

Step-by-step solution

aligned & K ₃ [ Fe ( OH )₆ ] & Fe ³⁺ 3 ~d ^5 & Fe ³⁺ with OH ⁻( WFL ) & = t ₂₉ ^3 e _ g ^2 aligned Number of unpaired electron ( n ) =5 spin only =5.92 BM aligned & K ₄ [ Fe ( OH )₆ ] & Fe ²⁺ OH ⁻ (WFL) & Fe ²⁺ 3 ~d ^6= t _ 2 ~g ^4 e _ g ^2 & n =4 aligned _ spin only =4.90 BM

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