For hydrogen atom, the orbital/s with lowest energy is/are : (A) 4 s (B) 3 p_x (C) 3 ~d_ x^2-y^2 (D) 3 ~d_ z^2 (E) 4 p_z Choose the correct answer from the options given below :

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Correct answer: A. (B), (C) and (D) only

For hydrogen atom and one electron species, the energy of orbitals is decided by the value of principal quantum number. Higher the value of principal quantum number, higher will be the energy of orbital. For hydrogen atom, the orbital/s with lowest energy is/are : (A) 4 s (B) 3 p_x (C) 3 ~d_ x^2-y^2 (D) 3 ~d_ z^2 (E) 4

For hydrogen atom, the orbital/s with lowest energy is/are : (A) 4 s (B) 3 p_x (C) 3 ~d_ x^2-y^2 (D) 3 ~d_ z^2 (E) 4

\therefore \quad(B),(C)

and (D) have orbitals with the lowest energy.

For hydrogen atom, the orbital/s with lowest energy is/are : (A) 4...

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