JEE Main 20249 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 9 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Structure of Atom
JEE Main 2024 · 9 April · Evening Shift · Chemistry · Structure of Atom
Based on Heisenberg's uncertainty principle, the uncertainty in the...
Based on Heisenberg's uncertainty principle, the uncertainty in the velocity of the electron to be found within an atomic nucleus of diameter (10^{-15} ) is ________. (10^9 ) (nearest integer)
[Given : mass of electron (=9.1 10^{-31} ), Plank's constant ((h)=6.626 10^{-34} )] (Value of (3.14))
Correct answer
0
Step-by-step solution
\begin{aligned} & \mathrm{m} \Delta \mathrm{V} . \Delta \mathrm{x}=\frac{\mathrm{h}}{4 \pi} \\ & \begin{aligned} \Delta \mathrm{V} & =\frac{6.626 \times 10^{-34}}{9.1 \times 10^{-31} \times 10^{-15} \times 4 \times 3.14} \\ & =57.97 \times 10^{+9} \mathrm{~m} / \mathrm{sec}\end{aligned}\end{aligned}$