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JEE Main 20248 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2024 · 8 April · Evening Shift · Chemistry · Structure of Atom

Wavenumber for a radiation having 5800 Ã… wavelength is (x × 10...

Wavenumber for a radiation having 5800A~…5800 Ã… wavelength is (x \times 10 \mathrm{~cm}^{-1}). The value of xx is ________ (Integer answer)

Correct answer

0

Step-by-step solution

vˉ(\bar{v}( wave no. )=1λ=15800×10−8 cm=17241)=\frac{1}{\lambda}=\frac{1}{5800 \times 10^{-8} \mathrm{~cm}}=17241 OR 1724×10 cm−1⇒x=17241724 \times 10 \mathrm{~cm}^{-1} \Rightarrow \mathrm{x}=1724
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