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JEE Main202431 Jan 2024Evening ShiftChemistryStructure of AtomActual

The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19 ) are

Options

  1. An = 4 , l = 2 , m = − 1 , s = + 1 2
  2. Bn = 4 , l = 0 , m = 0 , s = + 1 2
  3. Cn = 3 , l = 0 , m = − 1 , s = + 1 2
  4. Dn = 2 , l = 0 , m = 0 , s = + 1 2

Correct answer

B. n = 4 , l = 0 , m = 0 , s = + 1 2

Step-by-step solution

The set of numbers used to describe the position and energy of the electron in an atom are called quantum numbers. There are four quantum numbers, namely, principal, azimuthal, magnetic and spin quantum numbers. Electronic configuration of K is: K = Atomic number = 19 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 4 s 1 The outermost electron is in 4 s 1 ∴ n = 4 , l = 0 , m = 0 , s = + 1 2 Hence, the answer is option B.

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