The electron in the n th orbit of Li 2 + is excited to ( n + 1 ) orbit using the radiation of energy 1 . 47 × 10 - 17 J (as shown in the diagram). The value of n is ___________ Given : R H = 2 . 18 × 10 - 18 J

Step-by-step solution

The difference energy between two energy levels is ∆ E = 2 . 18 × 10 - 18   1 n 1 2 - 1 n 2 2   J 1 . 47 × 10 - 17 = 2 . 18 × 10 - 18 × ( 9 ) 1 ( n ) 2 - 1 ( n + 1 ) 2 0 . 749 = 1 n 2 - 1 ( n + 1 ) 2 n   =   1 Hence, the transition is taking place between 1 → 2 , and it comes under Lymann series. If we take 0 . 749 ≃ 0 . 75 = 3 4