If the uncertainty in velocity and position of a minute particle in...

$\Delta V = 2 . 4 \times {10}^{- 26}{ms}^{- 1}$

$\Delta x = {10}^{- 7}m$

$∵ \Delta p \cdot \Delta x = \dfrac{h}{4\pi}$

$∴ m \Delta V . \Delta x = \dfrac{h}{4\pi}$

$⇒ m \times 2 . 4 \times {10}^{- 26} \times {10}^{- 7} = \dfrac{6 . 626 \times {10}^{- 34}}{4 \times \pi}$

$m = \dfrac{6 . 626}{9 . 6 \times \pi} \times {10}^{- 1}$

$m = 0 . 02198kg$

$m = 21 . 98gm$

nearest integer $= 22$