If the uncertainty in velocity and position of a minute particle in space are, 2 . 4 × 10 - 26 ms - 1 and 10 - 7 m respectively. The mass of the particle in g is___(Nearest integer) (Given : h = 6 . 626 × 10 - 34 Js )

Step-by-step solution

ΔV = 2 . 4 × 10 - 26   ms - 1 Δx = 10 - 7   m ∵   Δp · Δx = h 4 π ∴   mΔV . Δx = h 4 π ⇒ m × 2 . 4 × 10 - 26 × 10 - 7 = 6 . 626 × 10 - 34 4 × π m = 6 . 626 9 . 6 × π × 10 - 1 m = 0 . 02198 kg m = 21 . 98 gm nearest integer = 22