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JEE Main202225 Jun 2022Evening ShiftChemistryStructure of AtomActual

The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is: [Given: The threshold frequency of platinum is 1 . 3 × 10 15 s - 1 and h = 6 . 6 × 10 - 34 Js ]

Options

  1. A8 . 58 × 10 - 19 J
  2. B9 . 76 × 10 - 20 J
  3. C3 . 21 × 10 - 14 J
  4. D6 . 24 × 10 - 16 J

Correct answer

A. 8 . 58 × 10 - 19 J

Step-by-step solution

Radiation energy = threshold energy of metal + kinetic energy of ejected electron For minimum energy, Radiation energy = threshold energy of metal E = hν E = 6 . 6 × 10 - 34 × 1 . 3 × 10 15 = 8 . 58 × 10 - 19 J

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