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A 50 watt bulb emits monochromatic red light of wavelength of 795   nm . The number of photons emitted per second by the bulb is x × 10 20 . The value of x is _____ . (Nearest integer)  [Given :  h = 6 . 63 × 10 - 34 Js  and   c = 3 . 0 × 10 8   ms - 1

Correct answer

0

Step-by-step solution

 Power  = 50   J / sec . time   =   1   sec . So ,   E =   50   J E = n h c λ n = 50 × 795 × 10 - 9 6 . 63 × 10 - 34 × 3 × 10 8 = 1998 . 5 × 10 17 ≅ 2 × 10 20

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