1kg of 0 . 75 molal aqueous solution of sucrose can be cooled up to...

Let mass of water initially present $= xg$

Mass of sucrose $= ( 1000 - x ) g$

Number of moles sucrose $= \dfrac{1000 - x}{342}$

Molality \left(M\right) = \dfrac{\dfrac{1000 - x}{342}}{x / 1000} = 0 . 75$</p><p>$2565 . 5x = {10}^{6} - 1000x$</p><p>$x = 795 . 86g$</p><p>no. of moles of sucrose$= 0 . 5969$</p><p>${\Delta T}_{f} = {ik}_{f}m$</p><p>$4 = 1 \times 1 . 86 \times \dfrac{0 . 5969}{( 795 . 86 - a ) g} \times 1000$</p><p>Ice separated$= 518 . 3g$