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JEE Main 202125 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
25 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2021 · 25 July · Morning Shift · Chemistry · Structure of Atom

A source of monochromatic radiation wavelength 400nm provides 1000J...

A source of monochromatic radiation wavelength 400nm400nm provides 1000J1000J of energy in 1010 seconds. When this radiation falls on the surface of sodium, x×1020x \times {10}^{20} electrons are ejected per second. Assume that wavelength 400nm400nm is sufficient for ejection of electron from the surface of sodium metal. The value of xx is ______. (Nearest integer)

\left(h = 6 . 626 \times {10}^{- 34}Js\right)$

Correct answer

0

Step-by-step solution

Total energy provided by

Source per second =100010=100J= \dfrac{1000}{10} = 100J

Energy required to eject electron =hcλ= \dfrac{hc}{\lambda}

=6.626×10−34400×10−9×3×108= \dfrac{6 . 626 \times {10}^{- 34}}{400 \times {10}^{- 9}} \times 3 \times {10}^{8}

Number of electrons ejected

=1006.626×10−34×3×108400×10−9= \dfrac{100}{\dfrac{6 . 626 \times {10}^{- 34} \times 3 \times {10}^{8}}{400 \times {10}^{- 9}}}

=400×10−7×10266.626×3= \dfrac{400 \times {10}^{- 7} \times {10}^{26}}{6 . 626 \times 3}

=40×10−206.626×3= \dfrac{40 \times {10}^{- 20}}{6 . 626 \times 3}

=2.01×1020= 2 . 01 \times {10}^{20}

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