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JEE Main202125 Feb 2021Evening ShiftChemistryStructure of AtomActual

Electromagnetic radiation of wavelength 663 nm is just sufficient to ionise the atom of metal A . The ionization energy of metal A in kJ mol - 1 is ___. (Rounded-off to the nearest integer) h = 6 . 63 × 10 - 34 Js , c = 3 . 00 × 10 8 ms - 1 , N A = 6 . 02 × 10 23 mol - 1

Correct answer

0

Step-by-step solution

E = hc λ × N A 1000 = 6 . 63 × 10 - 34 × 3 × 10 8 × 6 . 02 × 10 23 663 × 10 - 9 × 1000 = 3 × 6 . 02 × 10   kJ = 180 . 6   kJ

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