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JEE Main 202124 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Evening Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2021 · 24 February · Evening Shift · Chemistry · Structure of Atom

According to Bohr's atomic theory: (A) Kinetic energy of electron...

According to Bohr's atomic theory:
(A) Kinetic energy of electron is ∝Z2n2.∝ \dfrac{{Z}^{2}}{{n}^{2}} .
(B) The product of velocity (v) of electron and principal quantum number \left(n\right), ' vn ' ∝ {Z}^{2} .<br/>(C)Frequencyofrevolutionofelectroninanorbitis<br />(C) Frequency of revolution of electron in an orbit is∝ \dfrac{{Z}^{3}}{{n}^{3}} .<br/>(D)Coulombicforceofattractionontheelectronis<br />(D) Coulombic force of attraction on the electron is∝ \dfrac{{Z}^{3}}{{n}^{4}} .

Choose the most appropriate answer from the options given below:

Options

  1. A(A), (C) and (D) only
  2. B(A) and (D) only
  3. C(C) only
  4. D(A) only

Correct answer

B. (A) and (D) only

Step-by-step solution

According to the Bohr's atomic theory, the kinetic energy of an electron is directly proportional to the square of the atomic number and inversely proportional to the square of the principal quantum number.

(A) KE=13.6z2n2eVatom⇒KEαz2n2KE = 13 . 6\dfrac{{z}^{2}}{{n}^{2}}\dfrac{eV}{atom} ⇒ KE \alpha\dfrac{{z}^{2}}{{n}^{2}}

(B) speed of e−αzn{e}^{-}\alpha\dfrac{z}{n}

∴v×nαz∴ v \times n \alpha z

(C) Frequency of revolution of e−=v2πr{e}^{-} = \dfrac{v}{2\pi r}

∴∴ Frequency αz2n3\alpha\dfrac{{z}^{2}}{{n}^{3}}

(D) Coulombic force of attraction on the electron is directly proportional to the square of the atomic number and inversely proportional to the fourth power of the principal quantum number.

F=kq1q2r2=kze2r2{rαn2z)</p><p>F = \dfrac{{kq}_{1}{q}_{2}}{{r}^{2}} = \dfrac{{kze}^{2}}{{r}^{2}}\left\{r \alpha\dfrac{{n}^{2}}{z}\right)</p><p>⇒ F \alpha\dfrac{z}{{\left(\dfrac{{n}^{2}}{z}\right)}^{2}}</p><p></p><p>⇒ F \alpha\dfrac{{z}^{3}}{{n}^{4}}

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