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JEE Main 20205 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
5 September
Shift
Morning Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2020 · 5 September · Morning Shift · Chemistry · Structure of Atom

The difference between the radii of 3 ^ rd and 4 ^ th orbits of L _...

The difference between the radii of 3rd{3}^{rd} and 4th{4}^{\text{th}} orbits of Li2+{L}_{i}^{2 +} is ΔR1{\Delta R}_{1}. The difference between the radii of 3rd{3}^{rd} and 4th{4}^{\text{th}} orbits of He+{He}^{+} ΔR2.\Delta{R}_{2} . Ratio ΔR1:ΔR2\Delta{R}_{1}: \Delta{R}_{2} is :

Options

  1. A8:38: 3
  2. B3:83: 8
  3. C2:32: 3
  4. D3:23: 2

Correct answer

C. 2:32: 3

Step-by-step solution

r=0.529n27Ar = 0 . 529\dfrac{{n}^{2}}{7}A

For Li2+{Li}^{2 +}

(rL2+)n=4−(rL2+)n=3=0.5293[16−9]=ΔR1{\left(r{L}^{2 +}\right)}_{n = 4} - {\left(r{L}^{2 +}\right)}_{n = 3} = \dfrac{0 . 529}{3} [ 16 - 9 ] = \Delta{R}_{1}

For He+{He}^{+}

(rHe+)n=4−(rHe+)n=3=0.5292[16−9]=ΔR2{\left(r{He}^{+}\right)}_{n = 4} - {\left(r{He}^{+}\right)}_{n = 3} = \dfrac{0 . 529}{2} [ 16 - 9 ] = \Delta{R}_{2}

ΔR1ΔR2=23\dfrac{{\Delta R}_{1}}{{\Delta R}_{2}} = \dfrac{2}{3}

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