JEE Main201910 Apr 2019Evening ShiftChemistryStructure of AtomActual
The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9 . The spectral series are:
Options
- APaschen and Pfund
- BBalmer and Brackett
- CLyman and Paschen
- DBrackett and Pfund
Correct answer
C. Lyman and Paschen
Step-by-step solution
1 λ 2 = R H 1 n 1 2 - 1 n 2 2 1 λ 1 = R H 1 m 1 2 - 1 m 2 2 As for shortest wavelengths, n 2 and m 2 is ∞ . ∴     λ 1 λ 2 = 9 1 = m 1 2 n 1 2 Now if m 1 = 3 and n 1 = 1 it will justify the statement hence Lyman and Paschen B is correct.