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JEE Main201910 Apr 2019Morning ShiftChemistryStructure of AtomActual

The isoelectronic set of ions is:

Options

  1. AF - , L i + , N a + and M g 2 +
  2. BN 3 - , L i + , M g 2 + and O 2 -
  3. CN 3 - , O 2 - , F - and N a +
  4. DL i + , N a + , O 2 - and F -

Correct answer

C. N 3 - , O 2 - , F - and N a +

Step-by-step solution

In Isoelectronic species, number of electrons should be same Number of electrons present in Li + = 3 - 1 = 2 Number of electrons present in Na + = 11 - 1 = 10 (A) F - = 9 + 1 = 10 e - L i + = 3 - 1 = 2 e - N a + = 11 - 1 = 10 e - M g + 2 = 12 - 2 = 10 e - (B) N - 3 = 7 + 3 = 10 e - L i + = 3 - 1 = 2 e - M g + 2 = 12 - 2 = 10 e - N a + = 11 - 1 = 10 e - (C) F - = 9+1 = 10 O 2 - = 8+2 = 10 N 3 - = 7+3 = 10 M g 2 + = 12 - 2 = 10 (d) L i + = 3 - 1 = 2 e - N a + = 11 - 1 = 10 e - O - 2 = 8 + 2 = 10 e - F - = 9 + 1 = 10

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