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JEE Main201910 Jan 2019Evening ShiftChemistryStructure of AtomActual

The ground state energy of a hydrogen atom is - 13 .6 eV . The energy of second excited state of He + ion in eV is:

Options

  1. A- 27.2
  2. B- 6.04
  3. C- 3.4
  4. D- 54.4

Correct answer

B. - 6.04

Step-by-step solution

E = - 13 .6 z 2 n 2 = - 13 .6 2 2 3 2 = - 6 .04   eV (Second exited state = Third shell, n = 3 )

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