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JEE Main 201910 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
10 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2019 · 10 January · Evening Shift · Chemistry · Structure of Atom

The ground state energy of a hydrogen atom is - 13 .6 eV . The...

The ground state energy of a hydrogen atom is −13.6eV- 13 .6 eV. The energy of second excited state of He+{He}^{+} ion in eVeV is:

Options

  1. A−27.2- 27.2
  2. B−6.04- 6.04
  3. C−3.4- 3.4
  4. D−54.4- 54.4

Correct answer

B. −6.04- 6.04

Step-by-step solution

E=−13.6(z2n2)=−13.6(2232)=−6.04eVE = - 13 .6 \left(\dfrac{{z}^{2}}{{n}^{2}}\right) = - 13 .6 \left(\dfrac{{2}^{2}}{{3}^{2}}\right) = - 6 .04 eV

(Second exited state=Third shell, n=3n = 3)

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