If the principal quantum number n = 6 , the correct sequence of filling of electrons will be:

Step-by-step solution

As per n + l rule electrons fill first in that orbital which have least n + l value. When n + l values are same, then electron fills that orbital which have lowest n value. when n = 6 as per n + l rule when n = 6 ns subshell ⇒ 6 + 0 = 6 n − 1 d subshell ⇒ 5 + 2 = 7 n − 2 f subshell ⇒ 4 + 3 = 7 np subshell ⇒ 6 + 1 = 7 n s , n - 2 f , n - 1 d , n p n + l v a l u e s ⇒ 7 , 7 , 7 n v a l u e ⇒ 4 , 5 , 6