Given (A) n =5, ~m _ =+1 (B) n =2, =1, ~m _ =-1, ~m _ s =- l / 2 The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) are respectively:

Step-by-step solution

(i) n=5 means l=0,1,2,3,4 since m=+1 hence total no. of electrons will be =0 ( from s ) +2 (from p ) +2 (from d ) +2 ( from f ) +2 (from g ) =0+2+2+2+2=8 (ii) n =2, l=1, ~m _l=-1, ~m _ s =-1 / 2 represent 2 p orbital with one electron.