JEE Main2012ChemistryStructure of AtomActual
The following sets of quantum numbers represent four electrons in an atom. (i) n=4, l=1 (ii) n=4, l=0 (iii) n=3, l=2 (iv) n=3, l=1 The sequence representing increasing order of energy, is
Options
- A(iii) < (i) < (iv) < (ii)
- B(iv) < (ii) < (iii) < (i)
- C(i) < (iii) < (ii) < (iv)
- D(ii) < (iv) < (i) < (iii)
Correct answer
B. (iv) < (ii) < (iii) < (i)
Step-by-step solution
(i) 4 p (ii) 4 ~s (iii) 3 d (iv) 3 p According to Bohr Bury's (n+ ) rule, increasing order of energy will be (iv) < (ii) < (iii) < (i). Note: If the two orbitals have same value of (n+ ) then the orbital with lower value of n will be filled first.